3.328 \(\int x^{5/2} (a+b x)^2 (A+B x) \, dx\)

Optimal. Leaf size=63 \[ \frac {2}{7} a^2 A x^{7/2}+\frac {2}{11} b x^{11/2} (2 a B+A b)+\frac {2}{9} a x^{9/2} (a B+2 A b)+\frac {2}{13} b^2 B x^{13/2} \]

[Out]

2/7*a^2*A*x^(7/2)+2/9*a*(2*A*b+B*a)*x^(9/2)+2/11*b*(A*b+2*B*a)*x^(11/2)+2/13*b^2*B*x^(13/2)

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Rubi [A]  time = 0.03, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {76} \[ \frac {2}{7} a^2 A x^{7/2}+\frac {2}{11} b x^{11/2} (2 a B+A b)+\frac {2}{9} a x^{9/2} (a B+2 A b)+\frac {2}{13} b^2 B x^{13/2} \]

Antiderivative was successfully verified.

[In]

Int[x^(5/2)*(a + b*x)^2*(A + B*x),x]

[Out]

(2*a^2*A*x^(7/2))/7 + (2*a*(2*A*b + a*B)*x^(9/2))/9 + (2*b*(A*b + 2*a*B)*x^(11/2))/11 + (2*b^2*B*x^(13/2))/13

Rule 76

Int[((d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_))*((e_) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*
x)*(d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, d, e, f, n}, x] && IGtQ[p, 0] && (NeQ[n, -1] || EqQ[p, 1]) && N
eQ[b*e + a*f, 0] && ( !IntegerQ[n] || LtQ[9*p + 5*n, 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && Rational
Q[a, b, d, e, f])) && (NeQ[n + p + 3, 0] || EqQ[p, 1])

Rubi steps

\begin {align*} \int x^{5/2} (a+b x)^2 (A+B x) \, dx &=\int \left (a^2 A x^{5/2}+a (2 A b+a B) x^{7/2}+b (A b+2 a B) x^{9/2}+b^2 B x^{11/2}\right ) \, dx\\ &=\frac {2}{7} a^2 A x^{7/2}+\frac {2}{9} a (2 A b+a B) x^{9/2}+\frac {2}{11} b (A b+2 a B) x^{11/2}+\frac {2}{13} b^2 B x^{13/2}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 52, normalized size = 0.83 \[ \frac {2 x^{7/2} \left (143 a^2 (9 A+7 B x)+182 a b x (11 A+9 B x)+63 b^2 x^2 (13 A+11 B x)\right )}{9009} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(5/2)*(a + b*x)^2*(A + B*x),x]

[Out]

(2*x^(7/2)*(143*a^2*(9*A + 7*B*x) + 182*a*b*x*(11*A + 9*B*x) + 63*b^2*x^2*(13*A + 11*B*x)))/9009

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fricas [A]  time = 0.95, size = 56, normalized size = 0.89 \[ \frac {2}{9009} \, {\left (693 \, B b^{2} x^{6} + 1287 \, A a^{2} x^{3} + 819 \, {\left (2 \, B a b + A b^{2}\right )} x^{5} + 1001 \, {\left (B a^{2} + 2 \, A a b\right )} x^{4}\right )} \sqrt {x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)*(b*x+a)^2*(B*x+A),x, algorithm="fricas")

[Out]

2/9009*(693*B*b^2*x^6 + 1287*A*a^2*x^3 + 819*(2*B*a*b + A*b^2)*x^5 + 1001*(B*a^2 + 2*A*a*b)*x^4)*sqrt(x)

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giac [A]  time = 1.19, size = 53, normalized size = 0.84 \[ \frac {2}{13} \, B b^{2} x^{\frac {13}{2}} + \frac {4}{11} \, B a b x^{\frac {11}{2}} + \frac {2}{11} \, A b^{2} x^{\frac {11}{2}} + \frac {2}{9} \, B a^{2} x^{\frac {9}{2}} + \frac {4}{9} \, A a b x^{\frac {9}{2}} + \frac {2}{7} \, A a^{2} x^{\frac {7}{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)*(b*x+a)^2*(B*x+A),x, algorithm="giac")

[Out]

2/13*B*b^2*x^(13/2) + 4/11*B*a*b*x^(11/2) + 2/11*A*b^2*x^(11/2) + 2/9*B*a^2*x^(9/2) + 4/9*A*a*b*x^(9/2) + 2/7*
A*a^2*x^(7/2)

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maple [A]  time = 0.00, size = 52, normalized size = 0.83 \[ \frac {2 \left (693 B \,b^{2} x^{3}+819 A \,b^{2} x^{2}+1638 B a b \,x^{2}+2002 A a b x +1001 B \,a^{2} x +1287 a^{2} A \right ) x^{\frac {7}{2}}}{9009} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(5/2)*(b*x+a)^2*(B*x+A),x)

[Out]

2/9009*x^(7/2)*(693*B*b^2*x^3+819*A*b^2*x^2+1638*B*a*b*x^2+2002*A*a*b*x+1001*B*a^2*x+1287*A*a^2)

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maxima [A]  time = 0.81, size = 51, normalized size = 0.81 \[ \frac {2}{13} \, B b^{2} x^{\frac {13}{2}} + \frac {2}{7} \, A a^{2} x^{\frac {7}{2}} + \frac {2}{11} \, {\left (2 \, B a b + A b^{2}\right )} x^{\frac {11}{2}} + \frac {2}{9} \, {\left (B a^{2} + 2 \, A a b\right )} x^{\frac {9}{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)*(b*x+a)^2*(B*x+A),x, algorithm="maxima")

[Out]

2/13*B*b^2*x^(13/2) + 2/7*A*a^2*x^(7/2) + 2/11*(2*B*a*b + A*b^2)*x^(11/2) + 2/9*(B*a^2 + 2*A*a*b)*x^(9/2)

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mupad [B]  time = 0.06, size = 51, normalized size = 0.81 \[ x^{9/2}\,\left (\frac {2\,B\,a^2}{9}+\frac {4\,A\,b\,a}{9}\right )+x^{11/2}\,\left (\frac {2\,A\,b^2}{11}+\frac {4\,B\,a\,b}{11}\right )+\frac {2\,A\,a^2\,x^{7/2}}{7}+\frac {2\,B\,b^2\,x^{13/2}}{13} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(5/2)*(A + B*x)*(a + b*x)^2,x)

[Out]

x^(9/2)*((2*B*a^2)/9 + (4*A*a*b)/9) + x^(11/2)*((2*A*b^2)/11 + (4*B*a*b)/11) + (2*A*a^2*x^(7/2))/7 + (2*B*b^2*
x^(13/2))/13

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sympy [A]  time = 4.36, size = 80, normalized size = 1.27 \[ \frac {2 A a^{2} x^{\frac {7}{2}}}{7} + \frac {4 A a b x^{\frac {9}{2}}}{9} + \frac {2 A b^{2} x^{\frac {11}{2}}}{11} + \frac {2 B a^{2} x^{\frac {9}{2}}}{9} + \frac {4 B a b x^{\frac {11}{2}}}{11} + \frac {2 B b^{2} x^{\frac {13}{2}}}{13} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(5/2)*(b*x+a)**2*(B*x+A),x)

[Out]

2*A*a**2*x**(7/2)/7 + 4*A*a*b*x**(9/2)/9 + 2*A*b**2*x**(11/2)/11 + 2*B*a**2*x**(9/2)/9 + 4*B*a*b*x**(11/2)/11
+ 2*B*b**2*x**(13/2)/13

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